11x^2+12x-324=0

Solution for 11x^2+12x-324=0 equation:

11x^2+12x-324=0

a = 11; b = 12; c = -324;
Δ = b2-4ac
Δ = 122-4·11·(-324)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-120}{2*11}=\frac{-132}{22}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+120}{2*11}=\frac{108}{22}
=4+10/11
$